Question 549793
{{{-2x + 3y = -37.5}}}     (1)

{{{-4x + 0y = -24}}}       (2)


So for this question, I wouldn't use elimination as Equation (2) gives an easy way for solving for x, but we can

I will eliminate the x values. 
This means I must multiply my equation (1) by the constant in front of x in the second equation (2) (which is -4) which leaves:
{{{8x-12y=150}}}    (3) 
and my equation (2) by the constant in front of x in equation (1)(which is -2).  This leaves:
{{{8x+0y=48}}}      (4)

Now subtracting equation (3) by equation (4) we have:
{{{(8x-12y)-(8x+0y)=150-48}}} 
{{{-12y=102}}} 
{{{y=102/-12}}} 
{{{y=102/-12}}} 
{{{y=-8.5}}}


Now substituting this value of y back into any of the above equations (I will sub it into equation (2)), we can solve for x
{{{-4x + 0*-8.5 = -24}}} 
{{{-4x= -24}}} 
{{{x= -24/-4}}} 
{{{x= 6}}}


So the system has the solution (6, -8.5).  
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Hopefully this helps!
Romans 5:8