Question 549798

Note: *[Tex \LARGE \left(x_{1}, y_{1}\right)] is the first point *[Tex \LARGE \left(0,-5\right)]. So this means that {{{x[1]=0}}} and {{{y[1]=-5}}}.

Also, *[Tex \LARGE \left(x_{2}, y_{2}\right)] is the second point *[Tex \LARGE \left(6,0\right)].  So this means that {{{x[2]=6}}} and {{{y[2]=0}}}.



{{{m=(y[2]-y[1])/(x[2]-x[1])}}} Start with the slope formula.



{{{m=(0--5)/(6-0)}}} Plug in {{{y[2]=0}}}, {{{y[1]=-5}}}, {{{x[2]=6}}}, and {{{x[1]=0}}}



{{{m=(5)/(6-0)}}} Subtract {{{-5}}} from {{{0}}} to get {{{5}}}



{{{m=(5)/(6)}}} Subtract {{{0}}} from {{{6}}} to get {{{6}}}



So the slope of the line that goes through the points *[Tex \LARGE \left(0,-5\right)] and *[Tex \LARGE \left(6,0\right)] is {{{m=5/6}}}