<PRE><B>Question 549781</B>


{{{(y^2+9y+2)(y-8)}}} Start with the given expression.



{{{y^2(y-8)+9y(y-8)+2(y-8)}}} Expand.



{{{(y^2)*(y)+(y^2)*(-8)+(9y)*(y)+(9y)*(-8)+(2)*(y)+(2)*(-8)}}} Distribute.



{{{y^3-8*y^2+9*y^2-72*y+2*y-16}}} Multiply.



{{{y^3+y^2-70*y-16}}} Now combine like terms.



 So {{{(y^2+9y+2)(y-8)}}} expands to {{{y^3+y^2-70*y-16}}}.



In other words, {{{(y^2+9y+2)(y-8)=y^3+y^2-70*y-16}}}.
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