Question 549773
h=-16t^2-32t+320 gives the height of a ball thrown downward from the top of a 320 foot building with an initial velocity of 32 feet per second. Find the time in seconds that it takes for the ball to reach a height of 48 feet.
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Set h=-16t^2-32t+320 = 48
{{{-16t^2-32t+ 272 = 0}}}
{{{-t^2 - 2t + 17 = 0}}}
Solve for t