Question 1134
 Let the width of the border be x ft.
 Since the outer rectangular should be of dimensions 2x+29 and 2x+44.
 The area of the border = Area (outer rectangular -inner rectangular)
 We have (2x+29)(2x+44) - 29*44 = 474,
 Simplify: 4x^2 + 146 x = 474
 Or 2x^2 + 73 x - 237 = 0,
 Factoring (2x +79) (x -3) = 0 [Note: 237 =3 * 79]
 So, x = 3 or -79/2 (negative ,invalid)

 Answer: The uniform width of the border is 3 ft