Question 549712
use factor theorem.
 f(x) = x^3+2x^2-5x-6
 f(-1) = -1+2+5-6 = 0
 So, x+1 is a factor
 
By synthetic division, 
x^3+2x^2-5x-6 = (x+1)(x^2+x-6) = (x+1)(x-2)(x+3) = 0
 
 x = -1, 2, -3

m.ananth@hotmail.ca