Question 549596
Whenever you have an equation where the largest exponent on the y and x is 1, it is a line .  

To graph a line, it is easiest to put it in y=mx+b form (solve for y)


we have 
{{{2x+3y=6}}}
{{{2x+3y-2x=6-2x}}}
{{{3y=-2x+6}}}
{{{y=(-2/3)*x+(6/3)}}}
{{{y=(-2/3)*x+2}}}


So once we have it in this form we are automatically given a point on the line (since b is the y-intercept) which is (0,b) or in our case (0,2)

From there, we can use our m value (the slope which is rise over run) and get anotehr point.  In our case, we must go down 2 (since it is negative) and over 3

We end up with a graph like this:

{{{graph(300,300,-10,10,-10,10,(-2/3)*x+2)}}}