Question 549467
of usually means multiply, is usual means equals, so we get:
{{{(2/3)*n=4+(1/2)*n}}}
subtract {{{(1/2)*n}}} from both sides

{{{(2/3)*n-(1/2)*n=4}}}

to combine our like terms here, we have to remember back to subtracting fractions. We need a common denominator which will be 6

{{{(4/6)*n-(3/6)*n=4}}}
{{{(1/6)*n=4}}}
Now we need to divide both sides by 1/6 (which we do by multiplying by 6)
n=24