Question 549437

{{{sqrt(48k^7*q^8)}}}

Factorise 48 

{{{sqrt(2*2*2*2*3 k*k*k*k*k*k*k*q*q*q*q*q*q*q*q)}}}

Since you have to find the square root

There are 2 pairs of 2 so 2*2=4 balance is 3
There are 3 pairs of k so k^3 balance k
There are 4 pairs of k so q^4balance is 1

{{{4k^3sqrt(3k)*q^4}}}

{{{4k^3q^4sqrt(3k)}}}