Question 549397
{{{2(log((2x))-log(y))-(log(3)+2log(5))]]]
={{{2log((2x))-2log(y)-log(3)-2log(5)}}}
={{{log(((2x)^2))-log((y^2))-log(3)-log((5^2))}}}
={{{log((4x^2))-log((y^2))-log(3)-log(25)}}}
={{{log((4x^2))-(log((y^2))+log(3)+log(25))}}}
={{{log((4x^2))-log((3*25*y^2))}}}
={{{log((4x^2))-log((75*y^2))}}}
={{{log((4x^2/(5y^2)))}}}