Question 549353
{{{ln((2x+3)/(x^2-3x+2))^2}}}

Using the rule {{{(a/b)^x=(a^x)/(b^x)}}} we can write our equation as 
{{{ln(((2x+3)^2)/((x^2-3x+2)^2))}}}

Now using the rule {{{ln(a/b)=ln(a)-ln(b)}}} we can write our equation as
{{{ln((2x+3)^2)-ln((x^2-3x+2)^2)}}}

And finally using the rule {{{ln(a^x)=x*ln(a)}}} we can write our equation as
{{{2*ln(2x+3)-2*ln(x^2-3x+2)}}}

We could also factor out our common factor of 2 if we would like and get:
{{{2*(ln(2x+3)-ln(x^2-3x+2))}}}


Hopefully this helps!:) 
Bre