Question 549238
{{{10y+4x=20}}}
We need to graph this line.  
To do this, we need to isolate for y to get y=mx+b

{{{10y+4x-4x=20-4x}}}
{{{10y=20-4x}}}
{{{(10y)/10=(20-4x)/10}}}
{{{y=(20-4x)/10}}}
{{{y=(-4/10)*x+20/10}}}
{{{y=(-2/5)*x+2}}}


So we can first plot the y-intercept point (0,2) and then use the slope to get another point (go down 2 and over 5 since slope is rise over run)



This gives us the line:
{{{graph(300,300,-10,10,-10,10,(-2/5)*x+2)}}}