Question 548248
{{{(8/125)^(1/3)=root(3,8/125)}}}?
It so happens that {{{8=2^3}}} and {{{125=5^3}}}, so
{{{(8/125)^(1/3)=8^(1/3)/125^(1/3)=(2^3)^(1/3)/(5^3)^(1/3)=2^(3*(1/3))/5^(3*(1/3))=2^1/5^1=2/5}}}