Question 549292
Let the width of sidewalk be x 															
..															
Length of garden =			16	m  											
Width =12m  											
285-96=189 m^2															
Area =96m^2										
Area of sidewalk =189	m^2											
Length of ground + sidewalk =16								
width of ground + sidewalk = 				12+2x											
															
( 16+2x	)(12+2x	)-189=96
															
192+32x	+24x+4X^2-189	=	96
4X^2+56	x-93=	0					
Find the roots of the equation by quadratic formula														
	a=	4	b=	56	c=	-93									
	b^2-4ac=	3136	+	1488											
	b^2-4ac=	4624
	{{{sqrt(	4624	)}}}=	68							
	{{{x=(-b+-sqrt(b^2-4ac))/(2a)}}}														
	{{{x1=(-b+sqrt(b^2-4ac))/(2a)}}}														
	x1=(	-56	+	68	)/	8									
	x1=	1.5													
	x2=(-56	-68) /	8										
	x2= 	-15.5													
	Ignore negative value														
	width of sidewalk =		1.5	m