Question 549294
A picture has a height that is 4/3 its width. It is to be enlarged to have an area of 192 square inches. What will be the dimensions of the enlargement?.
:
Let x = the value of the multiplier
then the dimensions of the picture will be: 4x by 3x
:
the area
4x * 3x = 192
12x^2 = 192
x^2 = {{{192/12}}}
x^2 = 16
x = 4 is the multiplier
:
4*4 = 16 is the length
4*3 = 12 is the width