Question 549241
x+y<4
y<-x+4
-3x+2y>2
2y>3x+2
/2
y>(3/2)x+1

Find the x & y intercept points by plugging x=0,y=0 in both equations.								
equation I								
when x=	0	y=	4	(0,4)
when y =	0	x=	4(4,0)
Equation 2								
when x=	0	y=	1	(0,1)
when y =	0	x=	-0.67	(-0.67	,0	)

THE BOUNDARY								
{{{drawing(300,300,-10,10,-10,10,circle(0,4,0.3),circle(4,0,0.3),circle(0,1,0.3),circle(-0.67,0,0.3),graph(300,300,-10,10,-10,10,y=-x+4,y=(3/2)x+1))}}}

THE INEQUALITY
Since y is less than or greater thansomething draw a dotted line 
{{{drawing(300,300,-10,10,-10,10,circle(0,4,0.3),circle(4,0,0.3),circle(0,1,0.3),circle(-0.67,0,0.3),graph(300,300,-10,10,-10,10,y<-x+4,y>(3/2)x+1))}}}
			

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