Question 53520
(0+i^2)*(0+i^2)
(0)(0) + (0)(i^2)+(0)(i^2)+ (i^2)(i^2)
[Remember that the sqrt(-1)=i and that (-l)(-1)=i, so i^2=-1]

0+0+0+ (i^2)(i^2)
(i^2)(i^2)
(-1)(-1)
1