Question 549191
	--------percent	----------------	quantity									
Alcohol I	70	----------------			60	L						
Alcohol II	20	----------------			x	L						
Mixture	60	----------------	60	+	x	L						
												
70*60+20x=60(60+x)
4200	+	20	x	=3600+60x				
20	x	+	-60x=3600-4200				
-40	x	=	-600									
/	-40											
x	=	15										
		15	L		of			Alcohol II