Question 549176
Pythagoras theorem						
						
(Hyp)^2= (leg1)^2+Leg2^2	
Hypotenuse =	25	in		
leg1=		15	in		
Leg2=			?			
						
leg2^2=hyp^2-leg1^2						
Leg2^2=	25^2-15	^2
Leg2^2= 625-225		
Leg2^2= 400				
Leg2= 	{{{sqrt(175)}}}				
Leg2=	20	ft	

length = 20in

m.ananth@hotmail.ca