Question 549043
<pre>
{{{(4mn^3)/(10n^2)}}}  {{{4 = 2*2), {{{n^3 = n*n*n}}},  {{{10 = 2*5}}}, {{{n^2 = n*n}}}.  Substituting,

{{{(2*2*m*n*n*n)/(2*5*n*n)}}}

cancel a 2

{{{(cross(2)*2*m*n*n*n)/(cross(2)*5*n*n)}}}

cancel an n

{{{(cross(2)*2*m*cross(n)*n*n)/(cross(2)*5*cross(n)*n)}}}

cancel another n

{{{(cross(2)*2*m*cross(n)*cross(n)*n)/(cross(2)*5*cross(n)*cross(n))}}}

End up with:

{{{2mn/5}}}


Edwin</pre>