Question 549045
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You aren't sharing the entire problem.  You probably are dealing with a flat piece of material from which you cut *[tex \Large x] by *[tex \Large x] squares from the corner and then fold up the sides to make the box.  Then for a piece of material that originally measured *[tex \Large l] by *[tex \Large w], the bottom of the box would measure *[tex \Large l\ -\ 2x] by *[tex \Large w\ -\ 2x] and the height of the box would simply be *[tex \Large x].


Your function, for given constants *[tex \Large l] and *[tex \Large w], would be:


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ V(x)\ =\ x\left(l\ -\ 2x\right)\left(w\ -\ 2x\right)]


in its completely factored form.


The zeros of the polynomial would be where *[tex \Large x\ =\ 0] or where *[tex \Large x\ =\ \frac{w}{2}] presuming *[tex \Large w\ <\ l].   Note that *[tex \Large x\ =\ \frac{l}{2}] is also a zero of the polynomial but, again presuming *[tex \Large w\ <\ l], is a real world absurdity.


By the way, typing in all caps is the equivalent of shouting and is both rude and annoying.  Please don't apologize or make excuses -- just don't do it any more.


John
*[tex \LARGE e^{i\pi} + 1 = 0]
My calculator said it, I believe it, that settles it
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