Question 549040
<font face="Times New Roman" size="+2">


The sum of the measurses of the two shortest sides of a triangle must be strictly greater than the the measure of the longest side.


Assume that 19 is the longest side of the triangle, then the missing side that we can say measures *[tex \Large x] for the sake of discussion, must satisfy the inequality *[tex \Large 6\ +\ x\ >\ 19].  Which is to say, *[tex \Large x\ >\ 19\ -\ 6\ =\ 13]


Assume that *[tex \Large x] is the longest side of the triangle, then *[tex \Large x] must satisfy the following inequality: *[tex \Large x\ <\ 19\ +\ 6\ =\ 25]


Putting the two together:


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ 13\ <\ x\ <\ 25]


John
*[tex \LARGE e^{i\pi} + 1 = 0]
My calculator said it, I believe it, that settles it
<div style="text-align:center"><a href="http://outcampaign.org/" target="_blank"><img src="http://cdn.cloudfiles.mosso.com/c116811/scarlet_A.png" border="0" alt="The Out Campaign: Scarlet Letter of Atheism" width="143" height="122" /></a></div>
</font>