<PRE><B>Question 549022</B>
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In order to have a triangle, the sum of the two shorter sides must be strictly greater than the longest side.  Is *[tex \Large 12\ +\ 12\ &gt;\ 12]?


John
*[tex \LARGE e^{i\pi} + 1 = 0]
My calculator said it, I believe it, that settles it
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