Question 549012
Note: *[Tex \LARGE \left(x_{1}, y_{1}\right)] is the first point *[Tex \LARGE \left(0,32\right)]. So this means that {{{x[1]=0}}} and {{{y[1]=32}}}.

Also, *[Tex \LARGE \left(x_{2}, y_{2}\right)] is the second point *[Tex \LARGE \left(100,212\right)].  So this means that {{{x[2]=100}}} and {{{y[2]=212}}}.



{{{m=(y[2]-y[1])/(x[2]-x[1])}}} Start with the slope formula.



{{{m=(212-32)/(100-0)}}} Plug in {{{y[2]=212}}}, {{{y[1]=32}}}, {{{x[2]=100}}}, and {{{x[1]=0}}}



{{{m=(180)/(100-0)}}} Subtract {{{32}}} from {{{212}}} to get {{{180}}}



{{{m=(180)/(100)}}} Subtract {{{0}}} from {{{100}}} to get {{{100}}}



{{{m=9/5}}} Reduce



So the slope of the line that goes through the points *[Tex \LARGE \left(0,32\right)] and *[Tex \LARGE \left(100,212\right)] is {{{m=9/5}}}