Question 543066
how would you solve log 100 (^10^log10^12)
**
log10^12=12
base raised to a power=power.
10^log10^12=10^12
log 100 (^10^log10^12)=log 100^10^12=10^12*log 100
log 100=2
log 100 (^10^log10^12)=2(10^12) (ans)