Question 548913
Get log base 2 on both sides of equation
Note that {{{ -3 = log(2, 1/8) }}}, so
{{{ log(2, 8^x) = log(2, 1/8) }}}, therefore
{{{ 8^x = 1/8 }}}
{{{ 8^x = 8^-1 }}}
{{{ x = -1 }}}