Question 548863
length of pool	 4											
Width =	3								
Area =	12		M^2										
Area of sidewalk =44	M^2											
Length of ground + sidewalk =4								
width of ground + sidewalk =	12+2x											
															
(4+2x)(3+2x)-44	=12
12+8x+6x+4X^2-44=12
4X^2+14x-44=0
/2
2x^2+7x-22=0
2x^2+11x-4x-22=0
x(2x+11)-2(2x+11)=0
(x-2)(2x+11)=0
x=2 which is positive
width = 2ft