Question 548746
{{{25y^2=289}}} Start with the given equation.



{{{y^2=(289)/(25)}}} Divide both sides by {{{25}}}.



{{{y=""+-sqrt(289/25)}}} Take the square root of both sides.



{{{y=sqrt(289/25)}}} or {{{y=-sqrt(289/25)}}} Break up the "plus/minus" to form two equations.



{{{y=17/5}}} or {{{y=-17/5}}}  Take the square root of {{{289/25}}} to get {{{17/5}}}.



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Answer:



So the solutions are {{{y=17/5}}} or {{{y=-17/5}}}.



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