Question 548690
{{{A=LW}}}


{{{375=(2W-5)W}}}


{{{375=W(2W-5)}}}


{{{375=2W^2-5W}}}


{{{0=2W^2-5W-375}}}


{{{2W^2-5W-375=0}}}



Now use the quadratic formula to solve



{{{z = (-b+-sqrt(b^2-4ac))/(2a)}}}


{{{W = (-(-5)+-sqrt((-5)^2-4(2)(-375)))/(2(2))}}}


{{{W = (5+-sqrt(25-(-3000)))/(4)}}}


{{{W = (5+-sqrt(3025))/4}}}


{{{W = (5+sqrt(3025))/4}}} or {{{W = (5-sqrt(3025))/4}}}


{{{W = (5+55)/4}}} or {{{W = (5-55)/4}}}


{{{W = 60/4}}} or {{{W = -50/4}}}


{{{W = 15}}} or {{{W = -12.5}}}



So the width is 15 meters and the length is 2(15)-5 = 30-5 = 25 meters