Question 548633
mid point formula

(5-2)/2
3/2

(4+2)/2=3

(3/2,3)

x1		y1	x2	y2				
-2		2	5	4				
								
slope m =		(y2-y1)/(x2-x1)						
(	4	-	2	)/(	5	-	-2	) 
(	2	/	7	)  				
m=		  2/ 7		

The perpendicular will have slope of (-7/2) passes through (3/2,3)

m=		-7/ 2					
							
Plug value of  the slope  and point (	3/ 2	,	3	) in
Y 	=	m	x 	+	b		
3.00	=	-21/4	+	b			
b=	3	-	-21/4				
b=	33/ 4						
So the equation  will be							
Y 	=	-7/2	x 	+	33/4		
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