Question 548624
Pythagoras theorem						
						
(Hyp)^2= (leg1)^2+Leg2^2	
Hypotenuse =12	ft		
leg1=7	in		
Leg2=	?			
						
leg2^2=hyp^2-leg1^2						
Leg2^2= 		12	^2	-	7	^2
Leg2^2= 		144	-	49		
Leg2^2= 		95				
Leg2= 		{{{sqrt(175)}}}				
Leg2=		9.75	in