<PRE><B>Question 53430</B>
6/x - 2/x+3 = 3(x+5)/x(x+3)
:
Assume you mean:
:
{{{6/x - 2/(x+3) = 3(x+5)/x(x+3)}}}
:
Notice that the expression x(x+3) would be the common denominator; each denominator is a factor of x(x+3). If we mult the equation thru by x(x+3) we will effectively get rid of the denominators, we will have:
:
6(x+3) - 2x  = 3(x+5)
:
6x + 18 - 2x = 3x + 15
:
6x - 2x - 3x = 15 - 18
:
1x = -3
:
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However we find there is a problem here: in the term (x+3), if substitute -3 for x, we have 0 in denominators, a big no-no in algebra. I guess you will have to say there is no solution.
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