Question 548549
let the hypotenuse be x
it is 16 in longer than the shortest side
so shortest side = x-16
other side = x-2

By Pythagoras theorem

(x-2)^2+(x-16)^2=x^2

x^2-4x+4+x^2-32x+256=x^2
x^2-36x+260=0
x^2-26x-10x+260=0
x(x-26)-10(x-26)=0
(x-26)(x-10)=0
x=26 OR 10

Only 26 is possible

shortest side = 26-16=10
other side = 24

The sides are 10,24,26

CHECK
10^2+24^2=676 = 26^2