Question 548386
x^2+y^2=169
x+y=17

x=17-y

(17-y)^2+y^2=169

189-34y+y^2+y^2=169
20-34y+2y^2=0
/2
10-17y+y^2=0

y^2-17y+10=0
Find the roots of the equation by quadratic formula														
														
a=	1	,b=	-17	,c=	10									
														
b^2-4ac=	289	+	-40											
b^2-4ac=	249													
{{{x=(-b+-sqrt(b^2-4ac))/(2a)}}}							15.78							
{{{x1=(-b+sqrt(b^2-4ac))/(2a)}}}														
{{{x1=(-12+21)/(12)}}}														
x1=(	17	+	15.78	)/	2									
x1=	16.39													
x2=(	17	-15.78	) /	2										
x2= 	0.61													
x=16.39 so y=0.61	
x=0.61 so y=16.39										
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