Question 548276
Write and graph an equation for the parabola that has vertex (-1, 3) and passes through the point (-2, 1). Remember: y= a(x-h)2 + k
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y= a(x-h)^2 + k
y= a(x+1)^2 + 3
plug in coordinates of given point (-2,1) to find a
1= a(-2+1)^2 + 3
1= a(-1)^2 + 3
1= a + 3
a=-2
Equation:
y= -2(x+1)^2 + 3
see graph below:

{{{ graph( 300, 300, -5, 5, -5, 5, -2(x+1)^2 + 3) }}}