Question 548263
Given
Point (x, y)=(4,4) 
Line:
y=1/4(x)-5
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Compare given equation with Equation of line standard form (y=mx+b)
m=1/4
b=-5

Slope of the given line  m = 1/4 and y-intercept = b = -5

Since given line is parallel to the required line; slopes of the both line will be same.
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Now we have a point (4,4) and slope (1/4) of the required line we can easily find the required line by putting these values in the equation of slope-intercept form to find the y-intercept of the required line
y=mx+b
4=(1/4)(4)+b
4=4/4+b
4=1+b
4-1=b
3=b
b=3

y-intercept of the required line =b=3
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Put the values of ‘m’ and ‘b’ in equation of the line slope-intercept form
y=mx+b
y=(x/4)+3
Above equation is the required equation of the line in slope-intercept form.


Graph
Given line = y = x/4 - 5 (Red line)
Required line = y = x/4 +3 (Green line)
{{{ graph( 500, 500, -6, 5, -10, 10, x/4-5,x/4+3) }}}