<PRE><B>Question 548252</B>
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*[tex \Large (0,0)], *[tex \Large (5,0)], and *[tex \Large (5,-5)] are the vertices of an isosceles right triangle, hence:


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ \theta\ =\ \frac{3\pi}{4}]


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ \sin\left(\frac{3\pi}{4}\right)\ =\ \sin\left(\frac{\pi}{4}\right)\ =\ \frac{\sqrt{2}}{2}]


John
*[tex \LARGE e^{i\pi} + 1 = 0]
My calculator said it, I believe it, that settles it
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