Question 548209
First off there are 6 numbers to roll on the first die and 6 numbers to roll on the second die.  Therefore there are 6*6=36 total rolls that can be made.

If the numbers are doubles.  We have the following sums:
1+1=2
2+2=4
3+3=6
4+4=8
5+5=10
6+6=12

Looking at this we can see that there are 3 possible soubles that have a sum that is a multiple of 3 (2 and 2, 4 and 4, 6 and 6).  
therefore this probability is 
{{{3/36=1/12}}}