<PRE><B>Question 547974</B>
Let {{{ s }}} = speed of car leaving Vernon
{{{ s + 10 }}} = speed of car leaving Lewis
You can add their speeds to get speed of approach
{{{ 36/60 = .6 }}} hrs
1 hr 36 min = {{{ 1.6 }}} hrs
{{{ 152 = ( s + s + 10 )*1.6 }}}
{{{ 152 = ( 2s + 10 )* 1.6 }}}
{{{ 152 = 3.2s + 16 }}}
{{{ 3.2s = 152 - 16 }}}
{{{ 3.2s = 136 }}}
{{{ s = 42.5 }}}
{{{ s + 10 = 52.5 }}}
The speed of car leaving Vernon is 42.5 mi/hr
The speed of car leaving Lewis is 52.5 mi/hr</PRE>