Question 547807
{{{x-sqrt(2x)-4=2}}}

Let's get the square root on one side and everything else on another to get:
{{{x-sqrt(2x)-4+sqrt(2x)-2=2+sqrt(2x)-2}}}
{{{x-6=sqrt(2x)}}}

Now to get rid of the square root, we do the opposite of square root which is square both sides to get:
{{{(x-6)^2=(sqrt(2x))^2}}}
{{{(x-6)^2=2x}}}
{{{(x-6)(x-6)=2x}}}

Using the foil rule we get:
{{{x^2-12x+36=2x}}}
{{{x^2-12x+36-2x=2x-2x}}}
{{{x^2-14x+36=0}}}



I will let you try the rest from here... this is just a quadratic-- we know how to solve for x in this case (((HINT:  you have a special RULEs for QUADRATICS)))

Let me know if you are still unsure where to go from here!  Good luck!