<PRE><B>Question 547733</B>
	--------percent	----------------	quantity									
Antifreeze I	40	----------------			15	gallons						
Antifreeze II	80	----------------			x	gallons						
Mixture	55	----------------	15	+	x	gallons						
												
40*15+80x=55(15+x)
600+80x=25+55x				
80x+-55	x=	825	-	-600				
25x=225									
/	25											
x	=	9										
		9	gallons		of			Antifreeze II				
												
</PRE>