Question 547744
{{{(3m+5)/4 -(2m+6)/6 = m+2}}}

Let's first get rid of the 4 in the denominator by multiplying EACH term by 4
{{{4*(3m+5)/4 -4*(2m+6)/6 = 4*m+4*2}}}
{{{(3m+5) -(8m+24)/6 = 4m+8}}}

Now, let's get rid of the 6 in the denominator by multiplying EACH term by 6
{{{6*(3m+5) -6*(8m+24)/6 = 6*4m+6*8}}}
{{{18m+30 -(8m+24) = 24m+48}}}

And now distributing the negative on the left side into the bracket
{{{18m+30 -8m-24 = 24m+48}}}
{{{10m+6= 24m+48}}}

And putting everything with a m on one side and constants on the other:
{{{10m+6-10m-48= 24m+48-10m-48}}}
{{{6-48= 24m-10m}}}
{{{6-48= 24m-10m}}}
{{{-42=14m}}}
{{{-42/14=m}}}
{{{m=-3}}}



Hopefully this helps!