Question 547728
So for any parabola, we have the following possible transformations:

{{{y=a(x-h)^2+k}}} 
where (h,k) is the vertex, and a is the dilation and reflection.  


So from this we can see that  (-3,5) is the vertex, and we are reflecting it along the x axis (since a=-1).


So we have y=x^2(the base function) to begin

{{{graph(500,500,-10,10,-10,10,x^2)}}}

And now we reflect it along the x axis 
{{{graph(500,500,-10,10,-10,10,-x^2)}}}


And we use the vertex point (or slide the whole thing to the left 3 units and up 5 units
{{{graph(500,500,-10,10,-10,10,-(x+3)^2+5)}}}



We can also make a table of values and check if they match with our graph.  
Hopefully this helps!