Question 547736
{{{log(base6)y=log(base6)4-log(base6)x}}}

We need to first make the right hand side into one log using the rule 
log(a)+log(b)=log(ab)

So we have:
{{{log(base6)y=log(base6)(4*x)}}}

Now to get rid of the logs, we take raise the whole thing to it's base(normally logs are base 10, but in this case it is base 6):
{{{6^(log(base6)y)=6^(log(base6)(4*x))}}}
{{{y=4x}}}


Hopefully this helps:) let me know if you are still unsure.