Question 547653
Let
First integer = x+1
Second integer = x+2


The squares of two consecutive integers differ by 95.
{{{(x+2)^2-(x+1)^2=95}}}
{{{(x+2)^2-(x+1)^2=95}}}
{{{x^2+4x+4-x^2-2x-1=95}}}
{{{cross(x^2)+4x+4-cross(x^2)-2x-1=95}}}
{{{4x+4-2x-1=95}}}
{{{2x+3=95}}}
{{{2x=95-3}}}
{{{2x=92}}}
{{{2x/2=92/2}}}
{{{x=46}}}



First integer = x+1=46+1=47
Second integer = x+2=46+2=48