Question 547311
{{{log(x+3)+log(2)=1.1}}}

We need to first put this together as one log function.  Using the rule that says log(a)+log(b)=log(ab) we get 
{{{log((x+3)2)=1.1}}}

Now to get rid of the log, we must do the opposite function which is to put base 10 to the whole thing as so:
{{{10^(log((x+3)2))=10^(1.1)}}}
{{{(x+3)2=10^(1.1)}}}

Now we need to isolate x, to do this we must divide both sides by 2
{{{(x+3)=10^(1.1)/2}}}
And now we must subtract out the 3 
{{{x=10^(1.1)/2-3}}}

(This number can be done on your calculator and simplified... I will let you do the rest).  

Hopefully this helps, let me know if you are still unsure:)