Question 547261
g(x)= sqrt 5x-4
h(x)= 4x^2+7
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Find: h(g(x)) = h[g(x)] = h[sqrt(5x-4)] = 4((5x-4)+7 = 20x-9
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g(x)=5x^2-4x
h(x)= sqrt x-7 
find the domain of : g(h(x))
g[h(x)] = g[sqrt(x-7)] = 5(x-4)-4(sqrt(x-7) = 5x-20-4sqrt(x-7)
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Domain of g[h(x)] is All Real Numbers >= 7
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Cheers,
Stan H.
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