Question 53184
:
Solve:  LOGa(7x+1)=LOGa(4x+16)
:
I see this is a couple days old so no doubt you have figured out that:
"When the logs are equal the numbers are equal"

Therefore:
 7x+1 = 4x + 16
Solve:
 7x - 4x = 16 -1
       x = 15/3
       x = 5

Substitute:  7(5) + 1 = 4(5) + 16
:
Obviously log(36) = log(36)