Question 547135
<pre> 

 x² + 8x + 5 = 0

1x² + 8x + 5 = 0    Compare to

ax² + bx + c = 0  and get a=1, b=8, c=5 and substitute into:

{{{x = (-b +- sqrt( b^2-4*a*c ))/(2*a) }}}

{{{x = (-8 +- sqrt( 8^2-4*1*5 ))/(2*1) }}}

{{{x = (-8 +- sqrt(64-20 ))/2 }}}

{{{x = (-8 +- sqrt(44))/2 }}}

{{{x = (-8 +- sqrt(4*11))/2 }}}

{{{x = (-8 +- 2sqrt(11))/2 }}}

{{{x = -8/2 +- 2sqrt(11)/2 }}}

{{{x = -4 +- sqrt(11) }}}

Solutions are {{{-4 - sqrt(11) }}} and {{{-4 + sqrt(11) }}}

Edwin</pre>