Question 547051
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226 is even, hence divisible by 2.  226 divided by 2 is 113


113 is not even, so not divisible by 2.


113 sum of the digits is 5.  5 is not divisible by 3, so 113 is not divisible  by 3.


113 does not have 0 or 5 as a units digit.  113 is not divisible by 5.


113 is not divisible by 7.  (7 X 16 = 112)


113 is not divisible by 11.  (11 X 10 = 110, 11 X 11 = 121)


11 squared is 121 which is greater than 113.  Therefore 113 is prime.


226 = 2 X 113.


John
*[tex \LARGE e^{i\pi} + 1 = 0]
My calculator said it, I believe it, that settles it
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